17.3. Binary Trees Part 1¶
17.3.1. Binary Trees Part 1¶
17.3.1.1. Binary Trees¶
A binary tree is made up of a finite set of nodes that is either empty or consists of a node called the root together with two binary trees, called the left and right subtrees, which are disjoint from each other and from the root.
Notation: Node, children, edge, parent, ancestor, descendant, path, depth, height, level, leaf node, internal node, subtree.
17.3.1.2. A Recursive Data Structure¶
17.3.1.3. Binary Tree Node Class¶
interface BinNode { // Binary tree node ADT // Get and set the element value public Object value(); public void setValue(Object v); // return the children public BinNode left(); public BinNode right(); // return TRUE if a leaf node, FALSE otherwise public boolean isLeaf(); }interface BinNode<E> { // Binary tree node ADT // Get and set the element value public E value(); public void setValue(E v); // return the children public BinNode<E> left(); public BinNode<E> right(); // return TRUE if a leaf node, FALSE otherwise public boolean isLeaf(); }
17.3.1.4. Question¶
Write a recursive function named count that, given the root to a binary tree, returns a count of the number of nodes in the tree. Function count should have the following prototype:
int count(BinNode root)
17.3.1.5. Traversals¶
Any process for visiting the nodes in some order is called a traversal.
Any traversal that lists every node in the tree exactly once is called an enumeration of the tree’s nodes.
Preorder traversal: Visit each node before visiting its children.
Postorder traversal: Visit each node after visiting its children.
Inorder traversal: Visit the left subtree, then the node, then the right subtree.
17.3.1.6. Preorder Traversal (1)¶
static void preorder(BinNode rt) { if (rt == null) return; // Empty subtree - do nothing visit(rt); // Process root node preorder(rt.left()); // Process all nodes in left preorder(rt.right()); // Process all nodes in right }static <E> void preorder(BinNode<E> rt) { if (rt == null) { return; } // Empty subtree - do nothing visit(rt); // Process root node preorder(rt.left()); // Process all nodes in left preorder(rt.right()); // Process all nodes in right }
17.3.1.8. How not to write a traversal¶
// This is a bad idea static void preorder2(BinNode rt) { visit(rt); if (rt.left() != null) preorder2(rt.left()); if (rt.right() != null) preorder2(rt.right()); }// This is a bad idea static <E> void preorder2(BinNode<E> rt) { visit(rt); if (rt.left() != null) { preorder2(rt.left()); } if (rt.right() != null) { preorder2(rt.right()); } }Problems:This has a major bugIt puts the focus in the wrong place: Should focus on the current node, not the children. This version is therefore more complicated.
17.3.1.9. Recursion Examples¶
static int count(BinNode rt) { if (rt == null) return 0; // Nothing to count return 1 + count(rt.left()) + count(rt.right()); }static <E> int count(BinNode<E> rt) { if (rt == null) { return 0; } // Nothing to count return 1 + count(rt.left()) + count(rt.right()); }