30.12.1.1. Binary Trees¶

A binary tree is made up of a finite set of nodes that is either empty or consists of a node called the root together with two binary trees, called the left and right subtrees, which are disjoint from each other and from the root.

Notation: Node, children, edge, parent, ancestor, descendant, path, depth, height, level, leaf node, internal node, subtree.

30.12.1.2. A Recursive Data Structure¶

30.12.1.3. Binary Tree Node Class¶

• Java
• Processing
• Java (Generic)

interface BinNode { // Binary tree node ADT
  // Get and set the element value
  public Object value();
  public void setValue(Object v);

  // return the children
  public BinNode left();
  public BinNode right();

  // return TRUE if a leaf node, FALSE otherwise
  public boolean isLeaf();
}

interface BinNode { // Binary tree node ADT
  // Get and set the element value
  Object value();
  void setValue(Object v);

  // return the children
  BinNode left();
  BinNode right();

  // return TRUE if a leaf node, FALSE otherwise
  boolean isLeaf();
}

interface BinNode<E> { // Binary tree node ADT
  // Get and set the element value
  public E value();
  public void setValue(E v);

  // return the children
  public BinNode<E> left();
  public BinNode<E> right();

  // return TRUE if a leaf node, FALSE otherwise
  public boolean isLeaf();
}

30.12.1.4. Question¶

• Write a recursive function named count that, given the root to a binary tree, returns a count of the number of nodes in the tree. Function count should have the following prototype:

  int count(BinNode root)
  

30.12.1.5. Traversals¶

• Any process for visiting the nodes in some order is called a traversal.
• Any traversal that lists every node in the tree exactly once is called an enumeration of the tree's nodes.
• Preorder traversal: Visit each node before visiting its children.
• Postorder traversal: Visit each node after visiting its children.
• Inorder traversal: Visit the left subtree, then the node, then the right subtree.

30.12.1.6. Preorder Traversal (1)¶

• Java
• Processing
• Java (Generic)

static void preorder(BinNode rt) {
  if (rt == null) return; // Empty subtree - do nothing
  visit(rt);              // Process root node
  preorder(rt.left());    // Process all nodes in left
  preorder(rt.right());   // Process all nodes in right
}

void preorder(BinNode rt) {
  if (rt == null) return; // Empty subtree - do nothing
  visit(rt);              // Process root node
  preorder(rt.left());    // Process all nodes in left
  preorder(rt.right());   // Process all nodes in right
}

static <E> void preorder(BinNode<E> rt) {
  if (rt == null) return; // Empty subtree - do nothing
  visit(rt);              // Process root node
  preorder(rt.left());    // Process all nodes in left
  preorder(rt.right());   // Process all nodes in right
}

30.12.1.7. Preorder Traversal (2)¶

Settings

Saving...
Server Error
Resubmit

30.12.1.8. How not to write a traversal¶

• Java
• Processing
• Java (Generic)

// This is a bad idea
static void preorder2(BinNode rt) {
  visit(rt);
  if (rt.left() != null) preorder2(rt.left());
  if (rt.right() != null) preorder2(rt.right());
}

// This is a bad idea
void preorder2(BinNode rt) {
  visit(rt);
  if (rt.left() != null) preorder2(rt.left());
  if (rt.right() != null) preorder2(rt.right());
}

// This is a bad idea
static <E> void preorder2(BinNode<E> rt) {
  visit(rt);
  if (rt.left() != null) preorder2(rt.left());
  if (rt.right() != null) preorder2(rt.right());
}

Problems:

This has a major bug

It puts the focus in the wrong place: Should focus on the current node, not the children. This version is therefore more complicated.

30.12.1.9. Recursion Examples¶

• Java
• Processing
• Java (Generic)

static int count(BinNode rt) {
  if (rt == null) return 0;  // Nothing to count
  return 1 + count(rt.left()) + count(rt.right());
}

int count(BinNode rt) {
  if (rt == null) return 0;  // Nothing to count
  return 1 + count(rt.left()) + count(rt.right());
}

static <E> int count(BinNode<E> rt) {
  if (rt == null) return 0;  // Nothing to count
  return 1 + count(rt.left()) + count(rt.right());
}

Settings

Saving...
Server Error
Resubmit